A) 448 nm
B) 450 nm
C) 480 nm
D) 580 nm
Correct Answer: C
Solution :
Fringe width\[(\beta )\]is given by \[\beta =\frac{D\lambda }{d}\]where, D is separation between slits and screen, d is separation between two slits and\[\lambda \]is wavelength used. For given value of d and D Here, \[\beta \,\infty \lambda \] Therefore, we have \[\frac{10\,mm}{8\,mm}=\frac{63\times {{10}^{-7}}m}{{{\lambda }_{2}}}\]\[{{\lambda }_{2}}=\frac{6.3\times {{10}^{-7}}}{1.25}=480\,mm\] The wavelength of another source of laser light \[=480nm\]You need to login to perform this action.
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