A) \[u-2a\]
B) \[u-4a\]
C) \[2a-u\]
D) \[2a-3u\]
Correct Answer: B
Solution :
\[x=u(t-2s)+a{{(t+2s)}^{2}}\] \[v=\frac{dx}{dt}=u+2a(t-2s)\] \[v=\frac{dx}{dt}=u+2a(t-2)\] \[\therefore \]Initial velocity\[v(0)=u-4a\]You need to login to perform this action.
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