A) \[6.25\times {{10}^{-5}}m\]
B) \[6.25\times {{10}^{-3}}m\]
C) \[7.45\times {{10}^{+3}}m\]
D) \[8.9\times {{10}^{-4}}m\]
Correct Answer: A
Solution :
Given \[T=7.28\times {{10}^{-2}}N/m\] \[p=2.33\times {{10}^{3}}Pa\] The drop will evaporate if the water pressure greater than the vapour pressure p. i.e. \[p=\frac{2T}{R},\]where R = radius of drop \[\Rightarrow \] \[R=\frac{2T}{p}=\frac{2\times 7.28\times {{10}^{-2}}}{2.33\times {{10}^{3}}}=6.25\times {{10}^{-5}}m\]You need to login to perform this action.
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