A) 3
B) 6
C) 5
D) 4
Correct Answer: D
Solution :
\[|C{{u}^{II}}(N{{H}_{3}})||P{{t}^{II}}C{{l}_{4}}|\]shows \[|Cu(N{{H}_{3}})Cl||PtC{{l}_{3}}N{{H}_{3}}|,\] \[|Cu(N{{H}_{3}})C{{l}_{3}}||Pt{{(NH)}_{3}}Cl|\]and\[|CuC{{l}_{4}}||Pt{{(N{{H}_{3}})}_{4}}|\].Other isomers such as\[|Cu{{(N{{H}_{3}})}_{2}}C{{l}_{2}}||Pt{{(N{{H}_{3}})}_{2}}C{{l}_{2}}|\] does not exist due to both parts being neutral.You need to login to perform this action.
You will be redirected in
3 sec