A) It will diminish to 1/4 of the initial value
B) It will diminish to 1/8 of the initial value
C) It will grow four times
D) It will grow eight times
Correct Answer: B
Solution :
When volume is doubled, concentration are halved. Hence, new rate\[=k{{\left( \frac{a}{2} \right)}^{2}}\left( \frac{b}{2} \right)=\frac{1}{8}K{{a}^{2}}b\] i.e. it is\[\frac{1}{8}\]th of the initial value.
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