A) \[16:9\]
B) \[9:16\]
C) \[4:3\]
D) \[3:4\]
Correct Answer: D
Solution :
\[Y=\frac{Fl}{A\Delta l}\] Here\[y,l\]and F are constant So, \[\Delta l\propto \frac{1}{A}\] Also \[m=(V)\rho =(Al)\rho \] i.e. \[m\propto A\] \[\therefore \] \[\Delta l\propto \frac{1}{m}\] \[\Rightarrow \] \[\frac{\Delta {{l}_{1}}}{\Delta {{l}_{2}}}=\frac{{{m}_{2}}}{{{m}_{1}}}=\frac{3}{4}\] \[(\because {{m}_{1}}:{{m}_{2}}=4:3)\]You need to login to perform this action.
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