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MGIMS WARDHA MGIMS WARDHA Solved Paper-2015

  • question_answer
    In an AC circuit, voltage and current are given    by\[V=50\,\sin (100t)V\]and\[I=500\sin \left( 100t+\frac{\pi }{3} \right)A\]. The power dissipated in the circuit is

    A)  25W                                     

    B)  625W

    C)  1250W                

    D)  100W

    Correct Answer: B

    Solution :

                    Power dissipated in the circuit is \[p=\frac{{{V}_{0}}{{I}_{0}}}{2}\cos \phi \] \[=\frac{50\times 50}{2}\cos \frac{\pi }{3}\] \[=\frac{50\times 50}{2}\times \frac{1}{2}=25\times 25\] \[P=625W\]


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