MGIMS WARDHA MGIMS WARDHA Solved Paper-2015

  • question_answer
    A galvanometer has a resistance of\[4\,\Omega \]and a full scale deflection is produced by 12 mA current. What resistance must be connected in series with it to enable it to read 1.2 V?

    A)  \[45\,\Omega \]                             

    B)  \[96\,\Omega \]

    C)  \[80\,\Omega \]                             

    D)  \[40\,\Omega \]

    Correct Answer: B

    Solution :

                    Given \[G=4\,\Omega V=12V,{{I}_{g}}=12\,mA\] Let a resistance R be connected in series with the galvanometer then                 \[{{I}_{g}}=\frac{V}{R+G}\] \[\Rightarrow \]               \[12\times {{10}^{-3}}=\frac{12}{R+4}\] \[\Rightarrow \]               \[R+4=\frac{12}{12}\times {{10}^{3}}=100\]                 \[R=96\,\Omega \]


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