A)
B)
C)
D)
Correct Answer: C
Solution :
\[CB{{r}_{4}}+MeLi\xrightarrow[{}]{{}}MeBr+LiCB{{r}_{3}}\] \[LiCB{{r}_{3}}\xrightarrow[{}]{{}}LiBr+CB{{r}_{3}}\]
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