A) \[C{{H}_{3}}NC\xrightarrow[{}]{LiA{{H}_{4}}}\]
B) \[C{{H}_{3}}CN\xrightarrow[{}]{LiA{{H}_{4}}}\]
C) \[C{{H}_{3}}CON{{H}_{2}}\xrightarrow[{}]{LiA{{H}_{4}}}\]
D) \[C{{H}_{3}}CN{{H}_{2}}\xrightarrow[{}]{B{{r}_{2}}/KOH}\]
Correct Answer: A
Solution :
(a) \[C{{H}_{3}}NC\xrightarrow[{}]{LiAl{{H}_{4}}}\underset{Secondary\text{ }amine}{\mathop{C{{H}_{3}}NHC{{H}_{3}}}}\,\] (b)\[C{{H}_{3}}CN\xrightarrow[{}]{LiAl{{H}_{4}}}\underset{Primary\text{ }amine}{\mathop{C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}}}\,\] (c)\[C{{H}_{3}}CON{{H}_{2}}\xrightarrow[{}]{LiAl{{H}_{4}}}\underset{Primary\text{ }amine}{\mathop{C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}}}\,\] (d)\[C{{H}_{3}}CON{{H}_{2}}\xrightarrow[{}]{B{{r}_{2}}/KOH}\underset{Primary\text{ }amine}{\mathop{C{{H}_{3}}N{{H}_{2}}}}\,\]
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