| I. \[C{{H}_{3}}{{S}^{\text{O-}}}\] |
| II. \[C{{H}_{3}}{{O}^{\text{O-}}}\] |
| III. \[\overset{\text{O-}}{\mathop{O}}\,H\] |
| IV. \[Et{{O}^{\text{O-}}}\] |
A) II>III>IV>I
B) III>IV>I>II
C) IV>III>I>II
D) I>II>IV>III
Correct Answer: C
Solution :
Acidity is explained as \[C{{H}_{3}}SH>C{{H}_{3}}OH>{{H}_{2}}O>EtOH\] Basicity: \[C{{H}_{3}}{{S}^{\text{O-}}}<C{{H}_{3}}{{O}^{\text{O-}}}<\overset{\text{O-}}{\mathop{O}}\,H<EtO{{H}^{\text{O-}}}\] When nucleophilic centre is different (\[C{{H}_{3}}{{S}^{\text{O-}}}\] and\[C{{H}_{3}}{{O}^{\text{O-}}}\]) and they are from the same group, nucleophilicity is opposite to basicity. \[\therefore \] Nucleophilicity \[Et{{O}^{\text{O-}}}>\overset{\text{O-}}{\mathop{O}}\,H>C{{H}_{3}}{{S}^{\text{O-}}}>C{{H}_{3}}{{O}^{\text{O-}}}\] Hence, the answer is (c)
You need to login to perform this action.
You will be redirected in
3 sec
