A) 220 C
B) 340 C
C) 273.34 C
D) 280 C
Correct Answer: C
Solution :
Let\[dq\]be the small amount of charge which is passed in small interval of time\[dt\]. Then, \[dq=tdt=(5{{t}^{2}}+2t)dt\] So, the total charge passing through the cross-section of the wire during the time\[t=4\text{ }s\] to \[t=6s\] \[q=\int_{4}^{6}{(5{{t}^{2}}+2t)}dt\] \[=\left[ 5\frac{{{t}^{3}}}{3}+2\frac{{{t}^{2}}}{2} \right]_{4}^{6}\] \[=\frac{5}{3}({{6}^{3}}-{{4}^{3}})+({{6}^{2}}-{{4}^{2}})\] \[=\frac{5}{3}(216-64)+(36-16)\] \[q=\frac{5}{3}\times 152+20=27334\,C\]You need to login to perform this action.
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