A) \[52\,\mu A\]
B) \[42\,\mu A\]
C) \[32\,\mu A\]
D) \[26\,\mu A\]
Correct Answer: A
Solution :
Given, \[\alpha =0.96\] \[{{V}_{c}}=0.5V\] \[R=400\,\Omega \] So \[\beta =\frac{\alpha }{1-\alpha }\] \[=\frac{0.96}{1-0.96}=24\] The collector current\[{{I}_{c}}\]is given by \[{{I}_{C}}=\frac{{{V}_{C}}}{R}=\frac{0.5}{400}=1.25\,mA\] The base current is given by \[{{I}_{B}}=\frac{{{I}_{C}}}{\beta }=\frac{1.25\times {{10}^{-3}}}{24}=52.08\times {{10}^{-6}}A\] \[=52\mu A\]You need to login to perform this action.
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