A) 25W
B) 625W
C) 1250W
D) 100W
Correct Answer: B
Solution :
Power dissipated in the circuit is \[p=\frac{{{V}_{0}}{{I}_{0}}}{2}\cos \phi \] \[=\frac{50\times 50}{2}\cos \frac{\pi }{3}\] \[=\frac{50\times 50}{2}\times \frac{1}{2}=25\times 25\] \[P=625W\]You need to login to perform this action.
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