In this reaction: [AIPMT 2003] |
\[C{{H}_{3}}CHO+HCN\xrightarrow[{}]{{}}C{{H}_{3}}CH(OH)CN\]\[\xrightarrow{H.OH}C{{H}_{3}}CH(OH)COOH\] an asymmetric centre is generated. |
The acid obtained would be: |
A) 50% D + 50% L-isomer
B) 20% D + 80% L-isomer
C) D-isomer
D) L-isomer
Correct Answer: A
Solution :
[a] Lactice acid obtained in the given reaction is an optically active compound due to the presence of chiral C-atom. It exits as d and \[l\] forms whose ratio is 1 : 1. |
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