question_answer

A \[40\,\,\mu F\]capacitor is connected to a 200 V, 50 Hz ac supply. The rms value of the current in the circuit is, nearly:                                                                                                                                 [NEET 2020]

A)  2.05 A

B)       2.5 A

C)  25.1 A

D)       1.7 A

Correct Answer: B

Solution :

[b]        \[{{i}_{rms}}=c\omega \,{{\varepsilon }_{rms}}\]

\[\omega =2\pi f=100\,\pi \]

\[{{\varepsilon }_{rms}}=200\,\,V\]

\[\therefore {{i}_{rms}}=200\times 40\times {{10}^{-6}}\times 2\pi \times 50\]

\[=2.5\,A\]