A) 100 mA
B) 200 mA
C) 20 mA
D) 10 mA
Correct Answer: C
Solution :
Given, \[e=200\sqrt{2}\sin 100t\] |
and \[C=1\mu F\] |
\[{{E}_{rms}}=200\,V\] |
\[{{X}_{C}}=\frac{1}{\omega C}=\frac{1}{1\times {{10}^{-6}}\times 100}={{10}^{4}}\Omega \] |
\[{{i}_{rms}}=\frac{{{E}_{rms}}}{{{X}_{C}}}\] |
\[{{i}_{rms}}=\frac{200}{{{10}^{4}}}=2\times {{10}^{-2}}A=20mA\] |
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