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NEET Physics Atomic Physics NEET PYQ-Atomic Physics

  • question_answer
    When an \[\alpha -\]particle of mass 'm' moving with velocity \['v'\] bombards on a heavy nucleus of charge \['Ze'\], its distance of closest approach from the nucleus depends on m as :                                                        [NEET - 2016]

    A)  \[\frac{1}{m}\]            

    B) \[\frac{1}{\sqrt{m}}\]

    C)  \[\frac{1}{{{m}^{2}}}\]                     

    D)       m

    Correct Answer: A

    Solution :

    [a] At closest distance of approach, the kinetic energy of the particle will convert completely into electrostatic potential energy.
    \[\Rightarrow \]   \[\frac{1}{2}m{{v}^{2}}=\frac{KQq}{d}\Rightarrow d\propto \frac{1}{m}\]


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