A) (+) Sucrose
B) (+) Lactose
C) (+) Maltose
D) (-) Fructose
Correct Answer: A
Solution :
[a] Key Idea Reducing sugars' that exist in hemiacetal and hemiketal formsundergo mutarotation in aqueous solution. |
Among the given carbohydrates only sucrose is a non-reducing sugar as in it the hemiacetal and hemiketal groups of glucose and fructose are linked together through O-atom and thus not free. Due to the absence of free hemiacetal or hemiketal group sucrose does not exhibit mutarotation. |
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