A) \[A{{l}_{2}}{{O}_{3}}+HF+NaAl{{F}_{4}}\]
B) \[A{{l}_{2}}{{O}_{3}}+Ca{{F}_{2}}+NaAl{{F}_{4}}\]
C) \[A{{l}_{2}}{{O}_{3}}+N{{a}_{3}}Al{{F}_{6}}+Ca{{F}_{2}}\]
D) \[A{{l}_{2}}{{O}_{3}}+KF+N{{a}_{3}}Al{{F}_{6}}\]
Correct Answer: C
Solution :
[c] Alumina,
, is a bad conductor of electricity and has very high melting point, so before subjecting to electrolysis, it is mixed with fluorspar (
) and cryolite (
), which lower its melting point and make it more conducting.
You need to login to perform this action.
You will be redirected in
3 sec
