A) \[C{{l}_{2}}O<Cl{{O}_{2}}<ClO_{2}^{-}\]
B) \[C{{l}_{2}}O<C{{l}_{2}}O<ClO_{2}^{-}\]
C) \[C{{l}_{2}}O<ClO_{2}^{-}<ClO_{2}^{{}}\]
D) \[ClO_{2}^{-}<C{{l}_{2}}O<ClO_{2}^{{}}\]
Correct Answer: D
Solution :
Key Idea: As the number of tone pairs of electrons increases, bond angle decreases due to repulsion between Ip-Ip. Moreover, as the electro negativity of central atom decreases, bond angle decreases. |
Hence, the order of bond angle is |
(Cl is less electronegative as compared to O.) |
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