A) \[Cl{{F}_{3}}\]
B) \[B{{F}_{3}}\]
C) \[Al{{F}_{3}}\]
D) \[N{{F}_{3}}\]
Correct Answer: A
Solution :
In \[Cl{{F}_{3}}\] all bonds are not equal due to trigonal - bipyramidal (\[s{{p}^{3}}\] d-hybridisation) geometry of \[Cl{{F}_{3}}\] molecule. |
\[B{{F}_{3}}\] and \[Al{{F}_{3}}\] show trigonal symmetric structure due to \[s{{p}^{2}}\]-hybridisation. |
\[N{{F}_{3}}\] shows pyramidal geometry due to \[s{{p}^{3}}\] hybridisation. |
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