A) x\[Be_{2}^{+}\]
B) \[Be_{2}^{{}}\]
C) \[{{B}_{2}}\]
D) \[Li_{2}^{{}}\]
Correct Answer: B
Solution :
Key Idea Molecules with zero bond order, do not exist. |
[a] \[Be_{2}^{+}(4+4-1=7)=\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{1}}\] |
\[BO=\frac{4-3}{2}=0.5\] |
[b] \[B{{e}_{2}}(4+4=8)=\overset{{}}{\mathop{\sigma }}\,1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\overset{{}}{\mathop{\sigma }}\,2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}}\] |
\[BO=\frac{4-4}{2}=0\] |
[c] \[{{B}_{2}}(5+5=10)\] |
\[=\overset{{}}{\mathop{\sigma }}\,1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\overset{{}}{\mathop{\sigma }}\,2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}},\pi 2p_{x}^{1}\approx \pi 2p_{y}^{1}\] |
\[BO=\frac{6-4}{2}=1\] |
[d] \[L{{i}_{2}}(3+3=6)\] \[=\overset{{}}{\mathop{\sigma }}\,1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}}\] |
\[BO=\frac{4-2}{2}=1\] |
Thus, Be; does not exist under normal conditions. |
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