A) 414 s
B) 552 s
C) 690 s
D) 276 s
Correct Answer: C
Solution :
[c] Enzyme-catalysed reactions follow first order kinetics. |
\[\because \]Fall of concentration from 1.28 mg \[{{\text{L}}^{-1}}\]to |
\[\text{0}\text{.04}\,\text{mg}\,{{\text{L}}^{-1}}\] involves five half-lives. |
\[1.28\,\xrightarrow[{}]{{{T}_{1/2}}}0.64\xrightarrow[{}]{{{t}_{1/2}}}0.32\xrightarrow[{}]{{{t}_{1/2}}}0.16\] |
\[\xrightarrow[{}]{{{t}_{1/2}}}0.08\xrightarrow[{}]{{{t}_{1/2}}}0.04\] |
\[\therefore \]Time required \[=5\times {{t}_{1/2}}\] |
\[=5\times 138\,s\] |
= 690 s. |
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