A) Is tripled
B) Is doubled
C) Is halved
D) Remains unchanged
Correct Answer: B
Solution :
[b] Half-life of zero order |
\[{{t}_{1/2}}=\frac{[{{A}_{0}}]}{2K}\] |
\[{{t}_{1/2}}=\frac{[{{A}_{0}}]}{2K}\] |
\[{{t}_{1/2}}\] will be doubled on doubling the initial concentration. |
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