A) 200 s
B) 500 s
C) 1000 s
D) 100 s
Correct Answer: B
Solution :
[b] \[K\frac{2.303}{t}\log \frac{{{A}_{0}}}{A}\] (First order rate equation) |
\[4.606\times {{10}^{-3}}=\frac{2.303}{t}\log \frac{2}{0.2}\] |
\[t=\frac{2.303}{4.606\times {{10}^{-3}}}\times \log \,10\] |
\[=\frac{{{10}^{3}}}{2}=500\,\,\sec \] |
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