A) \[CI<F<O<S~~\]
B) \[O<S<F<Cl\]
C) \[F<S<O<Cl\]
D) \[S~<O<Cl<F\]
Correct Answer: B
Solution :
Key Idea Electron gain enthalpy, generally, increases in a period from left to right and decreases in a group on moving downwards. However, members of III period have somewhat higher electron gain enthalpy as compared to the corresponding members of second period, because of their small size. |
O and S belong to VI A(16) group and Cl and F belong to VII A(17) group. Thus, the electron gain enthalpy of Cl and F is higher as compared to O and S. |
Cl and \[F>O\] and S |
Between Cl and F, Cl has higher electron gain enthalpy as in P, the incoming electron experiences a greater force of -repulsion because of small size of F atom. Similar is true in case of O and S i.e., the electron gain enthalpy of S is higher as compared to O due to its small size. Thus, the correct order of electron gain enthalpy of given elements is \[O<S<F<Cl\] |
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