A) 1 g
B) 2 g
C) 10 g
D) 20 g
Correct Answer: A
Solution :
Equivalent wt. of dibasic acid \[=\frac{Mol\,.wt.}{2}\] |
\[=\frac{200}{2}=100\] |
Strength = 0.1 N, m = ?, V = 100 mL |
then, |
\[m=\frac{E\,V\,N}{1000}=\frac{100\times 100\times 0.1}{1000}=1\,g\] |
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