A) \[N{{H}_{3}}<\text{ }P{{H}_{3}}<\text{ }As{{H}_{3}}\]acidic
B) \[Li<Be<B<C-\]1st IP
C) \[A{{I}_{2}}{{O}_{3}}<MgO<N{{a}_{2}}O<{{K}_{2}}O\]basic
D) \[L{{i}^{+}}<N{{a}^{+}}<{{K}^{+}}<C{{s}^{+}}-\]ionic radius
Correct Answer: B
Solution :
| Li, Be, B and C are present in IInd period. In a period from left to right ionisarion potential increases. |
| \[\underset{Li\,\,\,Be\,\,B\,\,C}{\mathop{\xrightarrow{IP\,increases}}}\,\] |
| * But in case of Be and B, Be has higher IP than B due to stable configuration of Be |
| \[_{4}Be=1{{s}^{2}},\,2{{s}^{2}}\] \[\underset{2{{s}^{2}}}{\mathop{}}\,\,\,\text{stable configuration}\] |
| \[_{5}B=1{{s}^{2}},\,2{{s}^{2}}\,2{{p}^{1}}\]\[\underset{2{{p}^{1}}}{\mathop{}}\,\text{ unstable configuration}\] |
| So, the correct order of IP of given elements is |
| \[Li<B<Be<C\] |
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