NEET Chemistry NEET PYQ-Coordination Chemistry

  • question_answer
    The total number of possible isomers for the complex compound \[[C{{u}^{II}}{{(N{{H}_{3}})}_{4}}][P{{t}^{II}}C{{l}_{4}}]\] [AIPMT 1998]

    A) 3

    B) 6

    C) 5

    D) 4

    Correct Answer: D

    Solution :

    [d] Total isomers of the given complex are four. These are—
                (i) \[[Cu\,{{(N{{H}_{3}})}_{4}}]\,\,[PtC{{l}_{4}}]\]
                (ii) \[[Cu\text{ }{{(N{{H}_{3}})}_{3}}Cl]\,\,[Pt\,(N{{H}_{3}}\text{)}C{{l}_{3}}]\]
                (iii) \[[Pt\,{{(N{{H}_{3}})}_{3}}\,C{{l}_{2}}]\,[Cu\,{{(N{{H}_{3}})}_{2}}\,C{{l}_{2}}]\]
                (iv) \[[Pt\,{{(N{{H}_{3}})}_{4}}]\,\,[CuC{{l}_{4}}]\]


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