question_answer

Which statements is incorrect?    [AIPMT 2001]

A) \[Ni{{(CO)}_{4}}\]-Tetrahedral, paramagnetic      

B) \[Ni(CN)_{4}^{2-}\]-Square planar, diamagnetic

C) \[Ni{{(CO)}_{4}}\]-Tetrahedral, diamagnetic        

D) \[{{[Ni\,{{(Cl)}_{4}}]}^{2}}\]-Tetrahedral, paramagnetic

Correct Answer: C

Solution :

[c] In \[Ni{{(CO)}_{4}}\], Ni has zero oxidation number

So, \[_{28}Ni\text{ }=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{8}},\text{ }4{{s}^{2}}\]

In excited state and during the formation of \[Ni{{(CO)}_{4}}\to \]

Hence in it, no unpaired electron is present. So it shows the property of diamagnetism and tetrahedral structure.