A) it carries negative charge
B) it is a pseudo halide
C) it can accept electrons from metal species
D) it forms high spin complexes with metal species
Correct Answer: B
Solution :
| [b] \[\text{Hin}\rightleftharpoons {{\text{H}}^{\text{+}}}\text{+I}{{\text{n}}^{\text{-}}}\] |
| \[\therefore \]\[{{K}_{\text{ln}}}=\frac{[{{H}^{+}}][I{{n}^{-1}}]}{[HIn]}\] |
| or\[[{{H}^{+}}]={{K}_{\text{ln}}}.\frac{[HIn]}{[I{{n}^{-1}}]}\] |
| \[pH=-\log \,[{{H}^{+}}]\] |
| \[=-\log \left( {{K}_{\text{ln}}}\cdot \frac{[HIn]}{[I{{n}^{-}}]} \right)\] |
| \[=-\log \,{{K}_{\ln }}+\log \frac{[I{{n}^{-}}]}{[HIn]}\] |
| \[=p{{K}_{\ln }}+\log \frac{[I{{n}^{-}}]}{[HIn]}\] |
| or\[\log \frac{[I{{n}^{-}}]}{[HIn]}=pH-p{{K}_{\ln }}\] |
You need to login to perform this action.
You will be redirected in
3 sec
