NEET Chemistry NEET PYQ-Coordination Chemistry

  • question_answer
    Which one of the following is an inner orbital complex as well as diamagnetic in behaviour? [AIPMT (S) 2005]
                (Atomic no. : Zn = 30, Cr=24, Co=27, Ni = 28)

    A) \[{{[Zn\,{{(N{{H}_{3}})}_{6}}]}^{2+}}\]

    B) \[{{[Cr{{(N{{H}_{3}})}_{6}}]}^{3+}}\]         

    C) \[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}\]        

    D) \[{{[Ni\,{{(N{{H}_{3}})}_{6}}]}^{2+}}\]

    Correct Answer: B

    Solution :

    [b] In [Co(NH3)6]3+, oxidation state of Co = + 3 and its co-ordination number is six.
                So              \[_{27}Co=1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}}3{{p}^{6}},3{{d}^{7}},4{{s}^{2}}\]
                \[C{{o}^{3+}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{6}}\]
               
                In [Co(NH3)6]3+ shows inner orbital complex as well as diamagnetic in behaviour (due to absence of upaired electron).
                [Zn(NH3)6]3+ \[\to \] sp3d2  hybridisation   (outer) and diamagnetic.
                \[{{[Cr{{(N{{H}_{3}})}_{6}}]}^{2+}}\to \,{{d}^{2}}s{{p}^{3}}\] hybridisation   (inner) and paramagnetic.


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