A) \[3d_{{{x}^{2}}-{{y}^{2}}}^{1},\,3d_{{{z}^{2}}}^{1},\,3d_{xz}^{1}\]
B) \[3d_{xy}^{1},\,3d_{{{x}^{2}}-{{y}^{2}}}^{1},\,3d_{yz}^{1}\]
C) \[3d_{xy}^{1},\,3d_{zy}^{1},\,3d_{xz}^{1}\]
D) \[3d_{xy}^{1},\,3d_{yz}^{1},\,3d_{{{z}^{2}}}^{1}\]
Correct Answer: C
Solution :
| [c] Magnetic moment \[(\mu )=\sqrt{n(n+2)}\,BM\] |
| or \[3.83=\sqrt{n(n+2)}\,\] |
| or \[3.83\times 3.83={{n}^{2}}+2n\] |
| \[14.6689={{n}^{2}}+2n\] |
| on solving this, we get n = 3 |
| Hence, number of unpaired electrons in d-sub-shell of penultimate shell of chromium (Cr = 24). |
| So, the configuration of chromium ion is |
| Cr3+ = 1s2, 2s2 2p6, 3s2 3p6 3d3 |
| In [Cr(H2O)6]Cl2 oxidation state of Cr is +3) Hence, in 3d3 the distribution of electrons |
| \[3d_{xy}^{1},\,3d_{yz}^{1},\,3d_{zx}^{1},\,3d_{{{x}^{2}}-{{y}^{2}}}^{0},3d_{{{z}^{2}}}^{0}\] |
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