A) \[\frac{R}{4}\]
B) \[\frac{R}{8}\]
C) \[4\,R\]
D) \[\frac{R}{2}\]
Correct Answer: A
Solution :
| [a] When wire is bent to form a complete circle then |
| \[2\pi r=R\] |
| \[\Rightarrow \] \[r=\frac{R}{2\pi }\] |
| Resistance of each semicircle |
| \[=\pi r=\frac{\pi R}{2\pi }=\frac{R}{2}\] |
 |
| Thus, net resistance in parallel combination of two semicircular resistance. |
| \[R'=\frac{\frac{R}{2}\times \frac{R}{2}}{\frac{R}{2}+\frac{R}{2}}=\frac{\frac{{{R}^{2}}}{4}}{R}=\frac{R}{4}\] |
You need to login to perform this action.
You will be redirected in
3 sec
