A) 17.6 mg
B) 21.3 mg
C) 24.3 mg
D) 13.6 mg
Correct Answer: A
Solution :
| [a] Key Idea: The mass of a substance deposited or liberated at an electrode is directly proportional to the quantity of electricity i.e., charge passed through the electrolyte. |
| Power consumed in electrolysis, \[P=100\text{ }W\] |
| Voltage applied, \[V=125\text{ }V\] |
| So, current in the solution, |
| \[i=\frac{P}{V}=\frac{100}{125}=0.8\,A\] |
| According to first law of Faraday, mass liberated at an electrolyte is directly proportional to charge passed through the electrolyte i.e., |
| \[m\,\propto \,\,Q\Rightarrow \,m=zQ\] |
| where z is a constant called electro chemical equivalent (ECE). |
| Also \[Q=\]it |
| \[\therefore \] \[m=z\] it |
| Given, |
| \[z=0.367\times {{10}^{-6}}kg/C,\text{ }I=0.8\text{ }A,\text{ }t=60\,it\] |
| Hence, \[m=0.367\times {{10}^{-6}}\times 0.8\times 60\] |
| \[=17.6\times {{10}^{-6}}\,kg\] |
| \[=17.6\,mg\] |
| Note: Faraday has also discovered law of electromagnetic induction so while talking about Faradays law one must specify electrolysis or electromagnetic induction. |
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