A) \[450{}^\circ C\]
B) \[400{}^\circ C\]
C) \[{{225}^{o}}C\]
D) \[{{30}^{o}}C\]
Correct Answer: C
Solution :
[c] Given, \[E=30\theta -\frac{{{\theta }^{2}}}{15}\] at neutral temperature |
\[\frac{dE}{d\theta }=0\] |
\[\therefore \] \[30-\frac{2\theta }{15}=0\] |
\[\theta ={{225}^{o}}C\] |
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