A) 0.5 A
B) 0.25 A
C) 2 A
D) 1 A
Correct Answer: A
Solution :
[a] Effective resistance of a circuit, |
\[{{R}_{eff}}=40.8+\frac{480\times 20}{480+20}\] |
\[=40.8+19.2=60\Omega \] |
So, current flowing across ammeter, |
\[I=\frac{V}{R}=\frac{30}{60}=\frac{1}{2}=0.5A\] |
Hence, reading of ammeter \[=0.5\text{ }A\] |
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