NEET Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर NEET PYQ-Current Electricity Charging Capacitors

The thermo emf E in volt of a certain thermo-couple is found to vary with temperature difference \[\theta \] in \[^{o}C\] between the two junctions according to the relation \[E=30\,\theta -\frac{{{\theta }^{2}}}{15}\]. The neutral temperature for the thermo-couple will be                                                                                             [AIPMT (M) 2010]

A) \[450{}^\circ C\]

B)      \[400{}^\circ C\]

C) \[{{225}^{o}}C\]

D)      \[{{30}^{o}}C\]

Correct Answer: C

Solution :

[c] Given, \[E=30\theta -\frac{{{\theta }^{2}}}{15}\] at neutral temperature

\[\frac{dE}{d\theta }=0\]

\[\therefore \] \[30-\frac{2\theta }{15}=0\]

\[\theta ={{225}^{o}}C\]