A) 0.40 g
B) 0.50 g
C) 0.67 g
D) 0.27 g
Correct Answer: D
Solution :
[d] Key Idea: Apply first law of electrolysis during deposition of charge on an electrode through electrolysis. |
If m is the mass of a substance deposited or liberated at an electrode during electrolysis when a charge q passes through electrolyte, then according to Faraday's first law of electrolysis. |
\[m\,\propto \,\,q\] |
or \[m=zq\] |
where z is a constant of proportionality and is called electrochemical equivalent (ECE) of the substance. |
If an electric current \[I\] flows through the electrolyte, then |
\[q=it\] |
\[\therefore \] \[m=zit\] |
Here, mass of copper deposited on the electrode |
\[m=30\times {{10}^{-5}}\times 1.5\times 10\times 60\] |
\[=27\times {{10}^{-2}}=0.27\,g\] |
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