| The current \[(l)\] in the given circuit is: [AIPMT 1999] |
 |
A) 1.6 A
B) 2 A
C) 0.32 A
D) 3.2 A
Correct Answer: B
Solution :
| [b] In the given circuit resistances \[{{R}_{B}}\] and \[{{R}_{C}}\] are in series order, so their effective resistance, |
| \[R'={{R}_{B}}+{{R}_{C}}=6+6=12\,\Omega \] |
| Now \[{{R}_{A}}\] and \[R'\] are in parallel order, hence net resistance of the circuit |
| \[R=\frac{R'\times {{R}_{A}}}{R+{{R}_{A}}}=\frac{12\times 3}{12+3}=\frac{36}{15}\Omega \] |
| The current flowing in the circuit |
| \[I=\frac{V}{R}=4.8\,\times \frac{15}{36}=2A\] |
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