NEET Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर NEET PYQ-Current Electricity Charging Capacitors

  • question_answer
    If voltage across a bulb rated \[220\text{ }V-100\text{ }W\] drops by 2.5% of its rated value, the percentage of the rated value by which the power would decrease is                                                                                [AIPMT (S) 2012]

    A)  20%                

    B)       2.5%   

    C)  5%                  

    D)       10%

    Correct Answer: C

    Solution :

    [c] Power \[p=\frac{{{V}^{2}}}{R}\] for small variation
    \[\frac{\Delta P}{P}\times 100%=\frac{2\times \Delta V}{V}\times 100%\]
    \[=2\times 2.5=5%\]
    Therefore, power would decrease by 5%.


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