s
A) \[\frac{R}{{{n}^{2}}}\]
B) \[nR\]
C) \[\frac{R}{n}\]
D) \[{{n}^{2}}R\]
Correct Answer: D
Solution :
| [d] \[\frac{{{R}_{2}}}{{{R}_{1}}}=\frac{l_{2}^{2}}{l_{1}^{2}}\] |
| \[=\frac{{{n}^{2}}l_{1}^{2}}{l_{1}^{2}}\] |
| \[\frac{{{R}_{2}}}{{{R}_{1}}}={{n}^{2}}\] |
| \[{{R}_{2}}={{n}^{2}}{{R}_{1}}\] |
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