A) \[1.0\times {{10}^{1}}m\]
B) \[1.5\times {{10}^{1}}m\]
C) \[1.5\times {{10}^{2}}m\]
D) \[1.0\times {{10}^{2}}m\]
Correct Answer: A
Solution :
| [a] |
 |
| Initially, \[\frac{P}{10}=\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{3}{2}\] |
| \[\Rightarrow P=\frac{30}{2}=15\,\Omega \] |
| Now Resistance, \[R=\frac{{{p}^{l}}}{A}\] |
| \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{{{l}_{1}}}{{{l}_{2}}}\] |
| \[\Rightarrow \frac{15}{1}=\frac{1.5}{{{l}_{2}}}\] |
| \[{{l}_{2}}=0.1\,\,m\] |
| \[=1.0\times {{10}^{-1}}m\] |
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