A) \[\frac{1}{2}Mgl\]
B) \[\frac{1}{2}MgL\]
C) \[Mgl\]
D) \[MgL\]
Correct Answer: A
Solution :
[a] |
Loss in gravitational P.E. =\[Mgl\] |
Elastic potential energy |
\[U=\frac{1}{2}Mgl\] |
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