A) 300 V, 15 A
B) 450 V, 15 A
C) 450 V, 13.5 A
D) 600 V, 15 A
Correct Answer: B
Solution :
Initial power \[=3000\text{ }W\] |
As efficiency is 90% then final power |
\[=3000\times \frac{90}{100}\] |
\[=2700\,\,W\] |
\[\Rightarrow \] \[\left. \begin{align} & {{V}_{1}}{{l}_{1}}=3000\,\,W \\ & {{V}_{1}}{{l}_{1}}=2700\,\,W \\ \end{align} \right]\] (i) |
So, \[{{V}_{2}}\frac{2700}{6}=\frac{900}{2}=450V\] |
and \[{{l}_{1}}\frac{3000}{200}=15A\] |
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