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NEET Chemistry NEET PYQ-Electrochemistry

  • question_answer
    Limiting molar conductivity of \[N{{H}_{4}}OH\] \[(i.e.,\,\Delta {{m}_{(N{{H}_{4}}Cl)}})\] is equal to    [AIPMT (S) 2012]

    A) \[{{\Lambda }_{m(N{{H}_{4}}Cl)}}+{{\overset{o}{\mathop{\Lambda }}\,}_{m(NaCl)}}-{{\overset{o}{\mathop{\Lambda }}\,}_{m(NaOH)}}\]

    B) \[{{\overset{o}{\mathop{\Lambda }}\,}_{m}}_{(NaOH)}+{{\overset{o}{\mathop{\Lambda }}\,}_{m(NaCl)}}-{{\overset{o}{\mathop{\Lambda }}\,}_{m(N{{H}_{4}}Cl)}}\]

    C) \[{{\overset{o}{\mathop{\Lambda }}\,}_{m(N{{H}_{4}}OH)}}+{{\overset{o}{\mathop{\Lambda }}\,}_{m(N{{H}_{4}}Cl)}}-{{\overset{o}{\mathop{\Lambda }}\,}_{m(HCl)}}\]

    D) \[{{\overset{o}{\mathop{\Lambda }}\,}_{m(N{{H}_{4}}OH)}}+{{\overset{o}{\mathop{\Lambda }}\,}_{m(NaOH)}}-{{\overset{o}{\mathop{\Lambda }}\,}_{m(NaCl)}}\]

    Correct Answer: D

    Solution :

    [d] According to Kohlrausch's law, limiting molar conductivity of NH4OH \[\Lambda _{m\,(N{{H}_{4}}OH)}^{o}\,=\Lambda _{m\,(N{{H}_{4}}Cl)}^{o}+\Lambda {{_{m\,(NaOH)}^{o}}^{-}}\Lambda _{m\,(NaCl)}^{o}\,\]


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