A) \[E_{red}^{o}\] is negative
B) \[E_{red}^{o}\] is positive
C) \[\Delta {{G}^{o}}\] is negative
D) \[\Delta {{G}^{o}}\] is positive
Correct Answer: C
Solution :
| [c] \[\Delta G=\Delta H-T\Delta S\] |
| For a spontaneous cell reaction, \[\Delta H\] should be negative and \[\Delta S\] should be \[+\text{ }ve\] |
| Hence, \[\Delta G\] should be negative. |
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