A) In \[({{C}_{1}})\]
B) In \[({{C}_{2}}/{{C}_{1}})\]
C) In\[({{C}_{2}})\]
D) In \[({{C}_{1}}+{{C}_{2}})\]
Correct Answer: B
Solution :
[b] \[\Delta G=-n{{E}^{o}}\,F\] |
For concentration cell |
\[E=\frac{RT}{nF}\ln \,\frac{{{C}_{2}}}{{{C}_{1}}}\] |
In it R, T, n and F are constant. |
So E is based upon- In \[{{C}_{2}}/{{C}_{1}}\] |
\[\Delta G=-nEF\] |
\[=-nF\times \frac{RT}{nF}\ln \frac{{{C}_{2}}}{{{C}_{1}}}=-RT\,\ln \,\frac{{{C}_{2}}}{{{C}_{1}}}\] |
So, at constant temperature \[\Delta G\] depends upon In \[{{C}_{2}}/{{C}_{1}}\] |
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