| As a result of change in the magnetic flux linked to the closed loop shown in the figure, an emf V volt is induced in the loop. The work done (joules) in taking a charge Q coulomb once along the loop is: [AIPMT (S) 2005] |
 |
A) QV
B) zero
C) 2 QV
D) QV/2
Correct Answer: A
Solution :
| [a] Induced emf work done in taking a charge |
| \[=\frac{Q\,\,\text{once}\,\text{along}\,\text{the}\,\text{loop}}{\text{charge}\,Q}\] |
| i.e., \[V=\frac{W}{Q}\] |
| \[\Rightarrow \] \[W=VQ\] |
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